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solve-2-x-2-x-2x-




Question Number 172021 by Mikenice last updated on 23/Jun/22
solve:  2^x^2  =x^(2x)
solve:2x2=x2x
Answered by puissant last updated on 23/Jun/22
⇒  x^2 ln2 = 2xlnx  ⇒ xln2 = 2lnx  ⇒ ((lnx)/x)  =  ((ln2)/2)   ⇒   x=2
x2ln2=2xlnxxln2=2lnxlnxx=ln22x=2
Commented by mr W last updated on 23/Jun/22
 ((lnx)/x)=((ln2)/2)=((2×ln 2)/(2×2))=((ln 4)/4)  ⇒x=2, x=4    from (a/b)=(c/d) we get not only  a=c, b=d. but generally  a=kc, b=kd.
lnxx=ln22=2×ln22×2=ln44x=2,x=4fromab=cdwegetnotonlya=c,b=d.butgenerallya=kc,b=kd.
Commented by Tawa11 last updated on 25/Jun/22
Great sir
Greatsir

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