Solve-4x-2-8x-3-0-

Question Number 40212 by KMA last updated on 17/Jul/18

S o l v e 4 x^{2} - 8 x - 3 = 0

Commented by MJS last updated on 17/Jul/18

{a x}^{2} + b x + c = 0

x = - \frac{b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}

x^{2} + p x + q = 0

x = - \frac{p}{2} \pm \frac{\sqrt{p^{2} - 4 q}}{2}

Answered by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18

{(2 x)}^{2} - 2.2 x . 2 + 4 - 7 = 0

{(2 x - 2)}^{2} = 7

2 x = 2 \pm \sqrt{7}

x = \frac{2 \pm \sqrt{7}}{2}

Answered by Rio Mike last updated on 17/Jul/18

a = 4, b = - 8, c = - 3

x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

x = \frac{8 \pm \sqrt{64 - 12}}{8}

x = \frac{8 \pm 7.2}{8}

x = \frac{8 + 7.2}{8} o r \frac{8 - 7.2}{8}

Commented by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18

c h e c k t h e v a l u e o f 4 a c