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Question Number 172074 by Mikenice last updated on 23/Jun/22
solve: 5^(logx) =50−x^(log5)
solve:5logx=50−xlog5
Answered by aleks041103 last updated on 23/Jun/22
5^(logx) =10^(log5 logx) =(10^(logx) )^(log5) =x^(log5) ⇒2.5^(logx) =50 ⇒5^(logx) =25=5^2 ⇒logx=2 ⇒x=100
5logx=10log5logx=(10logx)log5=xlog5⇒2.5logx=50⇒5logx=25=52⇒logx=2⇒x=100

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