Menu Close

solve-by-Frobenius-method-x-2-y-x-2x-1-y-x-1-y-0-




Question Number 105361 by bemath last updated on 28/Jul/20
solve by Frobenius method  x^2 y′′−x(2x−1)y′+(x+1)y=0
$${solve}\:{by}\:{Frobenius}\:{method} \\ $$$${x}^{\mathrm{2}} {y}''−{x}\left(\mathrm{2}{x}−\mathrm{1}\right){y}'+\left({x}+\mathrm{1}\right){y}=\mathrm{0} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *