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solve-cosx-3-sinx-1-




Question Number 78946 by mathocean1 last updated on 21/Jan/20
solve  cosx−(√3)sinx=1
solvecosx3sinx=1
Commented by msup trace by abdo last updated on 21/Jan/20
e ⇔2((1/2)cosx−((√3)/2)sinx)=1 ⇒  cos((π/3))cosx−sin((π/3))sinx=(1/2)  ⇒cos(x+(π/3))=cos((π/3)) ⇒  x+(π/3) =(π/3)+2kπ or x+(π/3)=((2π)/3)+2kπ (kfrom Z)  ⇒x=3kπ or =(π/3)+2kπ
e2(12cosx32sinx)=1cos(π3)cosxsin(π3)sinx=12cos(x+π3)=cos(π3)x+π3=π3+2kπorx+π3=2π3+2kπ(kfromZ)x=3kπor=π3+2kπ
Commented by msup trace by abdo last updated on 21/Jan/20
error of typo  x=2kπ or x=(π/3)+2kπ
erroroftypox=2kπorx=π3+2kπ
Answered by Mr. AR last updated on 31/Jan/20
cos(90°−x)−(√3) sinx=1  sin x − (√3) sin x=1  sin x(1−(√3) )=1  sin x=(1/(1−(√3))) × ((1+(√3))/(1+(√3)))   sin x=((1+1.732)/(1−3))  sin x=((2.732)/(−2))  sin x=−1.366
cos(90°x)3sinx=1sinx3sinx=1sinx(13)=1sinx=113×1+31+3sinx=1+1.73213sinx=2.7322sinx=1.366

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