solve-d-2-y-dt-2-w-2-x-0-

Question Number 117608 by TANMAY PANACEA last updated on 12/Oct/20

s o l v e

\frac{d^{2} y}{{d t}^{2}} + w^{2} x = 0

Answered by Dwaipayan Shikari last updated on 12/Oct/20

\frac{d}{d t} (\frac{d y}{d t}) = - w^{2} x

\frac{d a}{d t} = - w^{2} x a = \frac{d y}{d t}

a = - w^{2} x t + C

\frac{d y}{d t} = - w^{2} x t + C \Rightarrow y = - \frac{w^{2}}{2} {x t}^{2} + C t + A