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Question Number 56052 by mr W last updated on 09/Mar/19
Solve following equation for x:  x^x^x^n   =n with n∈N
$${Solve}\:{following}\:{equation}\:{for}\:{x}: \\ $$$$\boldsymbol{{x}}^{\boldsymbol{{x}}^{\boldsymbol{{x}}^{\boldsymbol{{n}}} } } =\boldsymbol{{n}}\:{with}\:{n}\in\mathbb{N} \\ $$
Answered by MJS last updated on 09/Mar/19
x=(n)^(1/n)   is at least one solution  this seems true for n∈C\{0}
$${x}=\sqrt[{{n}}]{{n}} \\ $$$$\mathrm{is}\:\mathrm{at}\:\mathrm{least}\:\mathrm{one}\:\mathrm{solution} \\ $$$$\mathrm{this}\:\mathrm{seems}\:\mathrm{true}\:\mathrm{for}\:{n}\in\mathbb{C}\backslash\left\{\mathrm{0}\right\} \\ $$
Commented by mr W last updated on 09/Mar/19
thanks sir!
$${thanks}\:{sir}! \\ $$

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