Solve-for-complex-numbers-x-4-1-i-x-3-2ix-2-i-1-x-1-0-

Question Number 158274 by HongKing last updated on 01/Nov/21

Solve for complex numbers :

x^{4} + (1 + i) x^{3} + 2 {ix}^{2} + (i - 1) x - 1 = 0

Answered by mindispower last updated on 01/Nov/21

x = - 1, s o l u t i o n

(x + 1) (x^{3} + {i x}^{2} + i x - 1)

(x + 1) (x + i) (x^{2} + i)

(x + 1) (x + i) (x - e^{- \frac{i π}{4}}) (x - e^{\frac{3 i π}{4}})