Solve-for-natural-numbers-x-3-y-4-2022-

Question Number 150559 by mathdanisur last updated on 13/Aug/21

Solve for natural numbers :

x^{3} + y^{4} = 2022

Answered by MJS_new last updated on 13/Aug/21

if x = 0 : y^{4} = 2022 \Rightarrow y \approx 6.7

\Rightarrow y ⩽ 6

x = \sqrt[3]{2022 - y^{4}} with y = 1, 2, 3, 4, 5, 6

\Rightarrow no solution \in N

Commented by mathdanisur last updated on 13/Aug/21

Thanks Ser, if x = 1; 2; 3; . . ?

Commented by MJS_new last updated on 13/Aug/21

how could it make a difference ?

for 0 < y < 7 I tested all possible values

which natural number besides 1, 2, 3, 4, 5, 6

did I miss ?

Commented by mathdanisur last updated on 14/Aug/21

Thankyou Ser