Solve-for-real-numbers-1-x-1-2x-2-2x-1-x-2-

Question Number 163451 by HongKing last updated on 07/Jan/22

Solve for real numbers :

\sqrt{1 - x} = 1 - {2 x}^{2} + 2 x \sqrt{1 - x^{2}}

Commented by mr W last updated on 07/Jan/22

\sqrt{1 - x} = (1 - x^{2}) + 2 x \sqrt{1 - x^{2}} + x^{2}

\sqrt{1 - x} = {(\sqrt{1 - x^{2}})}^{2} + 2 x \sqrt{1 - x^{2}} + x^{2}

\sqrt{1 - x} = {(x + \sqrt{1 - x^{2}})}^{2}

\Rightarrow w e s e e x = 0

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