Solve-for-real-numbers-log-9-x-log-2-7-x-1-

Question Number 171360 by Shrinava last updated on 13/Jun/22

Solve for real numbers :

\log_{9} x \cdot \log_{2} (7 - x) = 1

Answered by MJS_new last updated on 13/Jun/22

\frac{\ln x}{2 \ln 3} \times \frac{\ln (7 - x)}{\ln 2} = 1

\ln x \ln (7 - x) = 2 \ln 3 \ln 2

\ln x \ln (7 - x) = \ln 3 \ln 4

obviously \Rightarrow

x_{1} = 3

x_{2} = 4

Commented by Rasheed.Sindhi last updated on 14/Jun/22

\cap i \subset\in sir!