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Solve-for-real-numbers-sin2x-4cos-2-x-1-cos5x-cosx-lt-0-




Question Number 156085 by MathSh last updated on 07/Oct/21
Solve for real numbers:  (sin2x + 4cos^2 x + 1)(cos5x - cosx)<0
$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\left(\mathrm{sin2x}\:+\:\mathrm{4cos}^{\mathrm{2}} \mathrm{x}\:+\:\mathrm{1}\right)\left(\mathrm{cos5x}\:-\:\mathrm{cosx}\right)<\mathrm{0} \\ $$$$ \\ $$

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