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Question Number 184622 by Shrinava last updated on 09/Jan/23
Solve for real numbers:  sinx (√(1 − sin^2 x)) = 1 + cosy (√(1 − cos^2 y))
Solveforrealnumbers:sinx1sin2x=1+cosy1cos2y
Answered by floor(10²Eta[1]) last updated on 09/Jan/23
sinxcosx=1+senycosy  ((sen(2x))/2)=1+((sen(2y))/2)  sen(2x)=2+sen(2y)  −1≤sen(2x)≤1  1≤2+sen(2y)≤3  ⇒sen2x=1=2+sen2y  ⇒sen2x=1 ∧ sen2y=−1  2x=(π/2)+2nπ ∧ 2y=((3π)/2)+2mπ  ⇒x=(π/4)+nπ ∧ y=((3π)/4)+mπ, m,n∈Z
sinxcosx=1+senycosysen(2x)2=1+sen(2y)2sen(2x)=2+sen(2y)1sen(2x)112+sen(2y)3sen2x=1=2+sen2ysen2x=1sen2y=12x=π2+2nπ2y=3π2+2mπx=π4+nπy=3π4+mπ,m,nZ

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