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Solve-for-real-numbers-the-following-system-of-equations-x-2-yz-3-y-2-xz-1-z-2-xy-1-




Question Number 152892 by mathdanisur last updated on 02/Sep/21
Solve for real numbers the following  system of equations:   { ((x^2  - yz = 3)),((y^2  - xz = 1)),((z^2  - xy = - 1)) :}
Solveforrealnumbersthefollowingsystemofequations:{x2yz=3y2xz=1z2xy=1
Commented by MJS_new last updated on 03/Sep/21
simply put y=px∧z=qx and it′s easy to solve
simplyputy=pxz=qxanditseasytosolve
Commented by mathdanisur last updated on 03/Sep/21
Yes, x=±(6/3) ; y=∓(2/3) ; z=±(1/3)
Yes,x=±63;y=23;z=±13

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