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Solve-for-real-numbers-x-2-3n-2-4n-2-4-2-n-y-1-x-2-3n-2-4n-2-4-2-n-z-1-x-2-3n-2-4n-2-4-2-n-x-1-n-0-fixed-




Question Number 160712 by HongKing last updated on 05/Dec/21
Solve for real numbers:  (((x^2 +3n^2 )/(4n^2 )))^4 = (2/n) y-1  ;  (((x^2 +3n^2 )/(4n^2 )))^4 = (2/n) z-1                        (((x^2 +3n^2 )/(4n^2 )))^4 = (2/n) x-1  n ∈ (0 ; ∞)  fixed
Solveforrealnumbers:(x2+3n24n2)4=2ny1;(x2+3n24n2)4=2nz1(x2+3n24n2)4=2nx1n(0;)fixed

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