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Question Number 176189 by Linton last updated on 14/Sep/22

s o l v e f o r x

{(1 + \frac{1}{x})}^{x + 1} = {(1 + \frac{1}{6})}^{6}

s h o w w o r k i n g

Answered by BaliramKumar last updated on 14/Sep/22

{(\frac{x + 1}{x})}^{x + 1} = {(1 + \frac{1}{6})}^{6}

{(\frac{x}{x + 1})}^{- (x + 1)} = {(1 + \frac{1}{6})}^{6}

{(\frac{x + 1 - 1}{x + 1})}^{- (x + 1)} = {(1 + \frac{1}{6})}^{6}

{(1 - \frac{1}{x + 1})}^{- (x + 1)} = {(1 + \frac{1}{6})}^{6}

p u t - (x + 1) = y

{(1 + \frac{1}{y})}^{y} = {(1 + \frac{1}{6})}^{6}

y = 6

- (x + 1) = 6

x + 1 = - 6

x = - 7 Answer