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Question Number 42627 by mondodotto@gmail.com last updated on 29/Aug/18
solve for x  (1/3)log(x−3)+log5−log(x−2)^2 =0
solveforx13log(x3)+log5log(x2)2=0
Answered by $@ty@m last updated on 30/Aug/18
log (x−3)+3log 5−3log (x−2)^2 =log 1  ((125(x−3))/((x−2)^6 ))=1  (x−2)^6 =125x−375  x^6 −6x^5 .2+15x^4 .2^2 −20x^3 .2^3                +15x^2 .2^4 −6x.2^5 +2^6 =125x−375  x^6 −12x^5 +60x^4 −160x^3 +240x^2           −317x+439=0  to be continue...
log(x3)+3log53log(x2)2=log1125(x3)(x2)6=1(x2)6=125x375x66x5.2+15x4.2220x3.23+15x2.246x.25+26=125x375x612x5+60x4160x3+240x2317x+439=0tobecontinue
Answered by ajfour last updated on 30/Aug/18
 ((125(x−3))/((x−2)^6 )) = 1  125(x−3)−(x−2)^6  = 0  ⇒  x ≈ 3.008  ,   x ≈ 4.351 .
125(x3)(x2)6=1125(x3)(x2)6=0x3.008,x4.351.
Commented by mondodotto@gmail.com last updated on 30/Aug/18
thank you sir
thankyousirthankyousir

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