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Question Number 45314 by mondodotto@gmail.com last updated on 11/Oct/18
solve for x  10^x =x^(50)
solveforx10x=x50
Answered by MrW3 last updated on 12/Oct/18
10^x =x^(50)   ±10^(x/(50)) =x  ±e^((x/(50))ln 10) =x  xe^(−(x/(50))ln 10) =±1  −((xln 10)/(50))e^(−(x/(50))ln 10) =∓((ln 10)/(50))  ⇒−((xln 10)/(50))=W(∓((ln 10)/(50)))  ⇒x=−((50)/(ln 10))W(∓((ln 10)/(50)))  = { ((−((50)/(ln 10))W(((ln 10)/(50)))=−((50×0.044066)/(ln 10))=−0.956881)),((−((50)/(ln 10))W(−((ln 10)/(50)))= { ((−((50×(−0.0483321))/(ln 10))=1.049518)),((−((50×(−4.605170))/(ln 10))=100)) :})) :}
10x=x50±10x50=x±ex50ln10=xxex50ln10=±1xln1050ex50ln10=ln1050xln1050=W(ln1050)x=50ln10W(ln1050)={50ln10W(ln1050)=50×0.044066ln10=0.95688150ln10W(ln1050)={50×(0.0483321)ln10=1.04951850×(4.605170)ln10=100
Commented by mondodotto@gmail.com last updated on 12/Oct/18
thanx atleast i get something
thanxatleastigetsomething
Commented by mondodotto@gmail.com last updated on 12/Oct/18
thanx a lot but i dont undstnd this method please can you explain sir
thanxalotbutidontundstndthismethodpleasecanyouexplainsir
Commented by MrW3 last updated on 12/Oct/18
Lambert W function is used.  If xe^x =a then x=W(a).
LambertWfunctionisused.Ifxex=athenx=W(a).
Commented by mondodotto@gmail.com last updated on 12/Oct/18
what is W
whatisW
Commented by MrW3 last updated on 12/Oct/18
To apply Lambert function to solve  the equation, all what we have to do  is to put the equation into a form like  Xe^X =Y  then we get X=W(Y).
ToapplyLambertfunctiontosolvetheequation,allwhatwehavetodoistoputtheequationintoaformlikeXeX=YthenwegetX=W(Y).
Commented by MrW3 last updated on 12/Oct/18
W(x) is the lambert function, defined  as W(x)e^(W(x)) =x.
W(x)isthelambertfunction,definedasW(x)eW(x)=x.

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