Solve-for-x-2-2x-4-x-2- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 54473 by Tawa1 last updated on 04/Feb/19 Solveforx:22x−4=x2 Answered by mr W last updated on 04/Feb/19 (2x−2)2=x22x−2=±x142x=±x14exln2=±x±14=xe−xln2±ln24=(−xln2)e−xln2−xln2=W(±ln24)⇒x=−1ln2W(±ln24)={−0.21530.30994 Commented by Tawa1 last updated on 04/Feb/19 Godblessyousir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-120006Next Next post: Question-120008 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.