solve-for-x-2-x-2-x-2-3-2-x-4-1-

Question Number 171815 by Mikenice last updated on 21/Jun/22

s o l v e f o r x :

{(2 - x^{2})}^{x^{2} - 3 \sqrt{2} x + 4} = 1

Answered by Rasheed.Sindhi last updated on 21/Jun/22

{(2 - x^{2})}^{x^{2} - 3 \sqrt{2} x + 4} = 1

c a s e 1 : 2 - x^{2} = 1 \Rightarrow x = \pm 1

c a s e 2 : x^{2} - 3 \sqrt{2} x + 4 = 0

x = \frac{3 \sqrt{2} \pm \sqrt{{(- 3 \sqrt{2})}^{2} - 4 (1) (4)}}{2 (1)}

x = \frac{3 \sqrt{2} \pm \sqrt{18 - 16}}{2}

x = \frac{3 \sqrt{2} \pm \sqrt{2}}{2} = 2 \sqrt{2}, \sqrt{2}

Commented by Mikenice last updated on 21/Jun/22

p l e a s e c o n t i n u e y o u r s o l u t i o n

Commented by Mikenice last updated on 21/Jun/22

p l e a s e c o n t i n u e y o u r s o l u t i o n