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solve-for-x-e-x-e-x-2-e-x-3-3-x-x-2-x-3-




Question Number 38587 by tawa tawa last updated on 27/Jun/18
solve for x:     e^x  + e^x^2   + e^x^3   =  3 + x + x^2  + x^3
solveforx:ex+ex2+ex3=3+x+x2+x3
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18
x=0
x=0
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18
left hand side curve...exponential and right  hand side curve...algebric...intersect...at one  point(0,3)
lefthandsidecurveexponentialandrighthandsidecurvealgebricintersectatonepoint(0,3)
Answered by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18
Answered by MrW3 last updated on 29/Jun/18
let′s have a look at the function  f(x)=e^x −x  f′(x)=e^x −1=0 ⇒x=0⇒f(0)=1  f′′(x)=e^x ⇒f′′(0)=1>0  that means f(x)=e^x −x has its minimum  at x=0 and the minimum is 1, or  in other words:  f(x)=e^x −x≥1  similarly e^x^2  −x^2 ≥1, e^x^3  −x^3 ≥1  ⇒(e^x −x)+(e^x^2  −x^2 )+(e^x^3  −x^3 )≥3  ⇒e^x +e^x^2  +e^x^3  ≥3+x+x^2 +x^3   the = sign is valid only at x=0.  that is to say  e^x +e^x^2  +e^x^3  =3+x+x^2 +x^3  has only  one solution x=0.
letshavealookatthefunctionf(x)=exxf(x)=ex1=0x=0f(0)=1f(x)=exf(0)=1>0thatmeansf(x)=exxhasitsminimumatx=0andtheminimumis1,orinotherwords:f(x)=exx1similarlyex2x21,ex3x31(exx)+(ex2x2)+(ex3x3)3ex+ex2+ex33+x+x2+x3the=signisvalidonlyatx=0.thatistosayex+ex2+ex3=3+x+x2+x3hasonlyonesolutionx=0.
Commented by tawa tawa last updated on 29/Jun/18
God bless you sir
Godblessyousir

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