Menu Close

Solve-for-x-in-0-2pi-sin-4x-pi-6-1-2-




Question Number 94877 by mathocean1 last updated on 21/May/20
Solve for x in [0;2π]:  sin(4x−(π/6))=(1/2)
Solveforxin[0;2π]:sin(4xπ6)=12
Commented by mathocean1 last updated on 21/May/20
Please sir, is there only 2 solutions   ∈ [0;2π] ?
Pleasesir,isthereonly2solutions[0;2π]?
Commented by mathocean1 last updated on 21/May/20
Thank you sir.
Thankyousir.
Answered by mr W last updated on 21/May/20
4x−(π/6)=2kπ+(π/6) ⇒x=((kπ)/2)+(π/(12))  4x−(π/6)=2kπ+π−(π/6) ⇒x=((kπ)/2)+(π/4)  within [0, 2π]:  x=(π/(12)), (π/4)  x=((7π)/(12)), ((3π)/4)  x=((13π)/(12)), ((5π)/4)  x=((19π)/(12)), ((7π)/4)
4xπ6=2kπ+π6x=kπ2+π124xπ6=2kπ+ππ6x=kπ2+π4within[0,2π]:x=π12,π4x=7π12,3π4x=13π12,5π4x=19π12,7π4
Commented by ElOuafi last updated on 22/May/20
this is the correct answer sir (8 solutions)!
thisisthecorrectanswersir(8solutions)!

Leave a Reply

Your email address will not be published. Required fields are marked *