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Solve-for-x-in-x-x-4-

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Question Number 116303 by Engr_Jidda last updated on 02/Oct/20
Solve for x in ϱ^x +x=4
Solveforxinϱx+x=4
Answered by mr W last updated on 02/Oct/20
ϱ^x =4−x ϱ^4 =ϱ^(4−x) (4−x) ϱ^4 =(4−x)e^((4−x)ln ϱ) ϱ^4 ln ϱ=[(4−x)ln ϱ] e^((4−x)ln ϱ) ⇒(4−x)ln ϱ=W(ϱ^4 ln ϱ) ⇒x=4−((W(ϱ^4 ln ϱ))/(ln ϱ))
ϱx=4−xϱ4=ϱ4−x(4−x)ϱ4=(4−x)e(4−x)lnϱϱ4lnϱ=[(4−x)lnϱ]e(4−x)lnϱ⇒(4−x)lnϱ=W(ϱ4lnϱ)⇒x=4−W(ϱ4lnϱ)lnϱ
Commented by Engr_Jidda last updated on 02/Oct/20
thank you sir
thankyousir

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