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Solve-for-x-log-log-6-x-1-64-6-




Question Number 160987 by cortano last updated on 10/Dec/21
 Solve for x         log _(log _6 (x−1)) (64) = 6
Solveforxloglog6(x1)(64)=6
Answered by bobhans last updated on 10/Dec/21
  log _(log _6 (x−1)) (64) = 6     [ log _6 (x−1)]^6  = 64    log _6 (x−1)= ± 2     (x−1)= { (6^(−2) ),(6^2 ) :}⇒ { ((x=1+(1/(36))=((37)/(36)))),((x=1+36=37)) :}
loglog6(x1)(64)=6[log6(x1)]6=64log6(x1)=±2(x1)={6262{x=1+136=3736x=1+36=37

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