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Question Number 17354 by ajfour last updated on 04/Jul/17
Solve for x :  ∣x−1∣−∣x−2∣+∣x+1∣>∣x+2∣+∣x∣−3 .
$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\:: \\ $$$$\mid\mathrm{x}−\mathrm{1}\mid−\mid\mathrm{x}−\mathrm{2}\mid+\mid\mathrm{x}+\mathrm{1}\mid>\mid\mathrm{x}+\mathrm{2}\mid+\mid\mathrm{x}\mid−\mathrm{3}\:. \\ $$
Commented by ajfour last updated on 04/Jul/17
my answer: x∈ (−3, 3)−{−1, 1 }  answer in book:  x∈ (1, 3) .
$$\mathrm{my}\:\mathrm{answer}:\:\mathrm{x}\in\:\left(−\mathrm{3},\:\mathrm{3}\right)−\left\{−\mathrm{1},\:\mathrm{1}\:\right\} \\ $$$$\mathrm{answer}\:\mathrm{in}\:\mathrm{book}:\:\:\mathrm{x}\in\:\left(\mathrm{1},\:\mathrm{3}\right)\:. \\ $$
Commented by ajfour last updated on 04/Jul/17
Commented by ajfour last updated on 04/Jul/17
isn′t this graph correct for   f(x)=∣x−1∣−∣x−2∣+∣x+1∣                 −∣x+2∣−∣x∣+3      ?
$$\mathrm{isn}'\mathrm{t}\:\mathrm{this}\:\mathrm{graph}\:\mathrm{correct}\:\mathrm{for} \\ $$$$\:\mathrm{f}\left(\mathrm{x}\right)=\mid\mathrm{x}−\mathrm{1}\mid−\mid\mathrm{x}−\mathrm{2}\mid+\mid\mathrm{x}+\mathrm{1}\mid \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\mid\mathrm{x}+\mathrm{2}\mid−\mid\mathrm{x}\mid+\mathrm{3}\:\:\:\:\:\:? \\ $$
Commented by mrW1 last updated on 04/Jul/17
your answer and graph are correct.
$$\mathrm{your}\:\mathrm{answer}\:\mathrm{and}\:\mathrm{graph}\:\mathrm{are}\:\mathrm{correct}. \\ $$
Commented by ajfour last updated on 04/Jul/17
thank you sir, immensely !
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir},\:\mathrm{immensely}\:! \\ $$

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