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Solve-for-x-x-i-x-2cx-cb-y-i-cx-2-cbx-0-the-following-is-true-for-this-equaition-i-c-gt-0-ii-b-gt-0-iii-there-is-only-one-real-solution-




Question Number 192363 by Red1ight last updated on 15/May/23
Solve for x  x_i −x+(2cx−cb)(y_i +cx^2 −cbx)=0  the following is true for this equaition  i)c>0  ii)b>0  iii)there is only one real solution
$$\mathrm{Solve}\:\mathrm{for}\:{x} \\ $$$${x}_{{i}} −{x}+\left(\mathrm{2}{cx}−{cb}\right)\left({y}_{{i}} +{cx}^{\mathrm{2}} −{cbx}\right)=\mathrm{0} \\ $$$$\mathrm{the}\:\mathrm{following}\:\mathrm{is}\:\mathrm{true}\:\mathrm{for}\:\mathrm{this}\:\mathrm{equaition} \\ $$$$\left.{i}\right)\mathrm{c}>\mathrm{0} \\ $$$$\left.{ii}\right)\mathrm{b}>\mathrm{0} \\ $$$$\left.{iii}\right)\mathrm{there}\:\mathrm{is}\:\mathrm{only}\:\mathrm{one}\:\mathrm{real}\:\mathrm{solution} \\ $$

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