solve-for-x-x-n-1-rx-n-1-x-n- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 175402 by Linton last updated on 29/Aug/22 solveforxxn+1=rxn(1−xn) Commented by a.lgnaoui last updated on 31/Aug/22 x1=rx0(1−x0)x2=rx1(1−x1)x3=rx2(1−x2)…….xn+1=rxn(1−xn)−−−−−−−−Πi=1n(xi)=rnΠxi(1−xi)=x1.x2.x3……xn1=rnx0(1−xn)xn=1−1x0rn(1)x1=rx0(1−x0)x2=rx1(1−x1)=r[rx0(1−x0)][1−rx0(1−x0)]=r2x0(1−x0)−r3x02(1−x0)2x3=rx2(1−x2)=[r(rx1(1−x1))][1−rx1(1−x1)]=r2x1(1−x1)−r3x12(1−x1)2x4=r2x2(1−x2)−r3x22(1−x2)2……..xn=r2xn−2(1−xn−2)−r3(1−xn−2)2Σxi=r[(r(x0(1−x0)+rx1(1−x1)+rx2(1−x2)+…..rxn−2(1−xn−2)−r×[r2[x0(1−x0)2+x12(1−x1)2+x32(1−x3)2+…..xn−22(1−xn−2)2Σxi=r[x1+x2+x3+….xn−1]+r[x12+x22+x32+…xn−12]?(1−r)Σxi=r(Σxi2)Σxi=rΣxi21−r?…………. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-109863Next Next post: d-2-y-dx-2-tan-x-dy-dx-0- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.