Question Number 103691 by MAB last updated on 16/Jul/20
$${solve}\:{for}\:{x} \\ $$$${x}^{{x}} ={s} \\ $$
Answered by Dwaipayan Shikari last updated on 16/Jul/20
$${xlogx}={logs} \\ $$$${logxe}^{{logx}} ={logs} \\ $$$${logx}={W}_{\mathrm{0}} \left({logs}\right) \\ $$$${x}={e}^{{W}_{\mathrm{0}} \left({logs}\right)} \\ $$
Commented by MAB last updated on 16/Jul/20
$${thanks}\:{sir} \\ $$