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solve-for-x-x-x-x-2-2048-by-using-lambert-function-




Question Number 183769 by Michaelfaraday last updated on 29/Dec/22
solve for x:  x^x^x  =2^(2048)   by using lambert function
solveforx:xxx=22048byusinglambertfunction
Commented by mr W last updated on 30/Dec/22
it has no solution by lambert!  no solution by anything!
ithasnosolutionbylambert!nosolutionbyanything!
Commented by mr W last updated on 30/Dec/22
4^4^4  =2^(512) <2^(2048)   5^5^5  =5^(3125) >2^(2048)   ⇒the root of x^x^x  =2^(2048)  lies between  4 and 5.
444=2512<22048555=53125>22048therootofxxx=22048liesbetween4and5.
Commented by Michaelfaraday last updated on 30/Dec/22
okay thanks sir
okaythankssir
Commented by paul2222 last updated on 03/Jan/23
we can use newton raphson iteration
wecanusenewtonraphsoniteration

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