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Question Number 93460 by john santu last updated on 13/May/20
solve for x,y >0  2x⌊y⌋ = 2020  3y⌊x⌋ = 2021
solveforx,y>02xy=20203yx=2021
Commented by john santu last updated on 13/May/20
ans : (((1010)/(673)) , ((2021)/3))
ans:(1010673,20213)
Answered by mr W last updated on 16/May/20
⌊x⌋=n≠0  ⌊y⌋=m≠0  2020=2x⌊y⌋≥2nm ⇒nm≤1010  2020=2x⌊y⌋<2(n+1)m ⇒(n+1)m≥1011  2021=3y⌊x⌋≥3mn⇒mn≤((2021)/3)=673  2021=3y⌊x⌋<3(m+1)n⇒n(m+1)≥674  ⇒m−n≥337  m≥337+n  mn=(337+n)n≤673  ⇒n=1 is the only solution  ⇒y=((2021)/3)  ⇒x=((1010)/(⌊((2021)/3)⌋))=((1010)/(673))
x=n0y=m02020=2xy2nmnm10102020=2xy<2(n+1)m(n+1)m10112021=3yx3mnmn20213=6732021=3yx<3(m+1)nn(m+1)674mn337m337+nmn=(337+n)n673n=1istheonlysolutiony=20213x=101020213=1010673

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