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Solve-in-N-6-x-6-y-222-




Question Number 172210 by Rasheed.Sindhi last updated on 24/Jun/22
Solve in N:  6^x +6^y =222
SolveinN:6x+6y=222
Commented by infinityaction last updated on 24/Jun/22
(1,3) and (3,1)
(1,3)and(3,1)
Commented by Rasheed.Sindhi last updated on 24/Jun/22
Correct sir! Process please!
Correctsir!Processplease!
Commented by infinityaction last updated on 22/Jul/22
x,y∈N   6^x +6^(y )  = 222  6^4  = 1296 ⪈ 222  so x and y ⪇ 4    and x and y ⪈0          0⪇x,y⪇4  so x and y should be 1,2,3   so  combitions of numbers   (x,y) = {(1,3) (3,1)}
x,yN6x+6y=22264=1296222soxandy4andxandy00x,y4soxandyshouldbe1,2,3socombitionsofnumbers(x,y)={(1,3)(3,1)}
Commented by Rasheed.Sindhi last updated on 24/Jun/22
ThanX sir!
ThanXsir!
Answered by Rasheed.Sindhi last updated on 24/Jun/22
AnOther Way  6^x +6^y =222  ⇒6^(x−1) +6^(y−1) =37  37 is sum of two powers of 6 and  one is certainly odd(6^0  is only odd)  ∴ 7=36+1 ∣ 7=1+36  ▶6^(x−1) +6^(y−1) =36+1=6^2 +6^0        x−1=2 ∧ y−1=0       x=3 ∧ y=1  ▶ 6^(x−1) +6^(y−1) =1+36=6^0 +6^2        x−1=0 ∧ y−1=2       x=1 ∧ y=3  (x,y)=(1,3),(3,1)
AnOtherWay6x+6y=2226x1+6y1=3737issumoftwopowersof6andoneiscertainlyodd(60isonlyodd)7=36+17=1+366x1+6y1=36+1=62+60x1=2y1=0x=3y=16x1+6y1=1+36=60+62x1=0y1=2x=1y=3(x,y)=(1,3),(3,1)
Commented by infinityaction last updated on 24/Jun/22
nice sir
nicesir
Commented by Rasheed.Sindhi last updated on 24/Jun/22
🙏🙏🙏
🙏🙏🙏
Answered by kapoorshah last updated on 24/Jun/22
6^(x − y) .6^y  + 6^y  = 222  6^y  (6^(x − y)  + 1) = 222  6^y  (6^(x − y)  + 1) = 6 . 37    6^y  = 6^1  ⇒ y = 1  6^(x − 1)  +1 = 37  6^(x − 1)  = 6^2  ⇒ x = 3    so the solutions : x = 3, y = 1 and                                         x = 1, y = 3
6xy.6y+6y=2226y(6xy+1)=2226y(6xy+1)=6.376y=61y=16x1+1=376x1=62x=3sothesolutions:x=3,y=1andx=1,y=3
Commented by Rasheed.Sindhi last updated on 24/Jun/22
Thanks sir!
Thankssir!

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