solve-in-N-b-3-2b-2-2b-1-18360-

Question Number 118196 by mathocean1 last updated on 15/Oct/20

s o l v e i n N :

b^{3} (2 b^{2} + 2 b + 1) = 18360

Answered by Olaf last updated on 15/Oct/20

b^{3} (b^{2} + {(b + 1)}^{2}) = 18360

> 2 b^{5} (\Rightarrow b ⩽ 6)

for b = 6 : 6^{3} (6^{2} + 7^{2}) = 18360

Commented by mathocean1 last updated on 15/Oct/20

p l e a s e c a n y o u d e t a i l t h e s e c o n d l i n e

Commented by Olaf last updated on 15/Oct/20

2 b^{5} \approx \overset{5}{} \sqrt{\frac{18360}{2}} \approx 6, 02

For b ⩾ 7 expression > 18360

For b = 6 expression = 18360 OK!

For b < 6 expression < 18360

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