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solve-in-N-n-4-42-n-2-

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Question Number 85224 by mathocean1 last updated on 20/Mar/20
solve in N (n−4)!=42(n−2)!
solveinN(n−4)!=42(n−2)!
Commented by jagoll last updated on 20/Mar/20
(n−4)! = 42(n−2)(n−3)(n−4)! 1 = 42(n−2)(n−3) n = ∅
(n−4)!=42(n−2)(n−3)(n−4)!1=42(n−2)(n−3)n=∅
Commented by mathocean1 last updated on 20/Mar/20
thank you sir! And this equation, what about it A_n ^4 =42A_n ^2 in N can help me to solve it?
thankyousir!Andthisequation,whataboutitAn4=42An2inNcanhelpmetosolveit?
Commented by jagoll last updated on 20/Mar/20
A_n ^4 −42A_n ^2 = 0 A_n ^2 (A_n ^2 −42) = 0 { ((A_n ^2 = 0 )),((A_n ^2 =42)) :} . what is A_n is this case?
An4−42An2=0An2(An2−42)=0{An2=0An2=42.whatisAnisthiscase?
Commented by mathocean1 last updated on 20/Mar/20
A_n ^2 =((n!)/((n−2)!)) ?
An2=n!(n−2)!?
Commented by mathocean1 last updated on 20/Mar/20
So i can have n!=42(n−2)!
Soicanhaven!=42(n−2)!
Commented by mathocean1 last updated on 20/Mar/20
(n−1)!×(n−2)!=42(n−2)! so (n−1)!=42 but how can i have the value[of n?
(n−1)!×(n−2)!=42(n−2)!so(n−1)!=42buthowcanihavethevalue[ofn?
Commented by jagoll last updated on 20/Mar/20
n! = 42 (n−2)! n (n−1)(n−2)! = 42 (n−2)! n^2 −n−42=0 (n−7)(n+6)=0 n = 7 ←this solution
n!=42(n−2)!n(n−1)(n−2)!=42(n−2)!n2−n−42=0(n−7)(n+6)=0n=7←thissolution

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