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Solve-in-R-59-x-2-1-3-12-x-11-1-3-6-




Question Number 47993 by F_Nongue last updated on 18/Nov/18
Solve in R  ((59+(√(x−2))))^(1/3) +((12−(√(x−11))))^(1/3) =6
SolveinR59+x23+12x113=6
Commented by tanmay.chaudhury50@gmail.com last updated on 18/Nov/18
x=27
x=27
Commented by ajfour last updated on 18/Nov/18
steps please..
stepsplease..
Commented by MJS last updated on 18/Nov/18
we can try  or  we can eliminate all roots which leads to  a polynome of 5^(th)  degree ⇒ we can only try  again. is there an easier way?  [putting x=t+((13)/2) helps while transforming]
wecantryorwecaneliminateallrootswhichleadstoapolynomeof5thdegreewecanonlytryagain.isthereaneasierway?[puttingx=t+132helpswhiletransforming]
Commented by MJS last updated on 18/Nov/18
trying to find x with both x−2 and x−11  are square numbers we get x=11 or x=27  but only x=27 fits  f(x)=((59+(√(x−2))))^(1/3) +((12−(√(x−11))))^(1/3) −6 is decreasing  for x≥11 ⇒ there′s only 1 solution
tryingtofindxwithbothx2andx11aresquarenumberswegetx=11orx=27butonlyx=27fitsf(x)=59+x23+12x1136isdecreasingforx11theresonly1solution
Commented by tanmay.chaudhury50@gmail.com last updated on 18/Nov/18
from problem...    1)x>2 and x>11  i have solved logically  6=1+5  6=2+4  6=3+3  that means  59+(√(x−2)) =64  x−2=25   x=27  12−(√(x−11)) =8  (√(x−11)) =4  x=27
fromproblem1)x>2andx>11ihavesolvedlogically6=1+56=2+46=3+3thatmeans59+x2=64x2=25x=2712x11=8x11=4x=27

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