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solve-in-R-8-x-4-1-5-x-3-1-7x-2-12-




Question Number 91872 by  M±th+et+s last updated on 03/May/20
solve in R  8(√(x^4 +1))+5(√(x^3 +1))=7x^2 +12
$${solve}\:{in}\:\mathbb{R} \\ $$$$\mathrm{8}\sqrt{\mathrm{x}^{\mathrm{4}} +\mathrm{1}}+\mathrm{5}\sqrt{\mathrm{x}^{\mathrm{3}} +\mathrm{1}}=\mathrm{7x}^{\mathrm{2}} +\mathrm{12} \\ $$
Commented by MJS last updated on 03/May/20
you can  { (((square+transform)×2 and then)),((     approximate the 8^(th)  degree polynome)),((or approximate the given equation)) :}  I get  x_1 ≈−.367792  x_2 ≈.440570  x_3 ≈1.16117
$$\mathrm{you}\:\mathrm{can}\:\begin{cases}{\left(\mathrm{square}+\mathrm{transform}\right)×\mathrm{2}\:\mathrm{and}\:\mathrm{then}}\\{\:\:\:\:\:\mathrm{approximate}\:\mathrm{the}\:\mathrm{8}^{\mathrm{th}} \:\mathrm{degree}\:\mathrm{polynome}}\\{\mathrm{or}\:\mathrm{approximate}\:\mathrm{the}\:\mathrm{given}\:\mathrm{equation}}\end{cases} \\ $$$$\mathrm{I}\:\mathrm{get} \\ $$$${x}_{\mathrm{1}} \approx−.\mathrm{367792} \\ $$$${x}_{\mathrm{2}} \approx.\mathrm{440570} \\ $$$${x}_{\mathrm{3}} \approx\mathrm{1}.\mathrm{16117} \\ $$
Commented by  M±th+et+s last updated on 03/May/20
thanks sir but can you show the steps  of the solution
$${thanks}\:{sir}\:{but}\:{can}\:{you}\:{show}\:{the}\:{steps} \\ $$$${of}\:{the}\:{solution} \\ $$
Commented by  M±th+et+s last updated on 03/May/20
and the values are correct
$${and}\:{the}\:{values}\:{are}\:{correct} \\ $$

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