Question Number 107064 by mathocean1 last updated on 08/Aug/20
$${Solve}\:{in}\:\mathbb{R} \\ $$$${x}+\sqrt{−{x}^{\mathrm{2}} +{x}+\mathrm{6}}=\sqrt{\mathrm{2}{x}\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{6}}−{x}} \\ $$
Answered by Her_Majesty last updated on 09/Aug/20
$${defined}\:{for}\:\mathrm{0}\leqslant{x}\leqslant\mathrm{3} \\ $$$${we}\:{can}\:{only}\:{approximate} \\ $$$${I}\:{get}\:{x}\approx\mathrm{2}.\mathrm{444955781} \\ $$