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Question Number 84293 by M±th+et£s last updated on 11/Mar/20
solve in R x^([x]) +x^(2−[x]) =x^2 +1
solveinRx[x]+x2−[x]=x2+1
Answered by TANMAY PANACEA last updated on 12/Mar/20
when 1>x≥0 L=x^0 +x^(2−0) =1+x^2 =R so x∈[0,1)
when1>x⩾0L=x0+x2−0=1+x2=Rsox∈[0,1)

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