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solve-in-x-C-sin-x-3-2-




Question Number 153568 by liberty last updated on 08/Sep/21
solve in x∈C   sin x=(3/2)
solveinxCsinx=32
Answered by Ar Brandon last updated on 08/Sep/21
sinx=(3/2) ⇒e^(ix) −e^(−ix) =3i  ⇒e^(2ix) −3ie^(ix) −1=0 ⇒e^(ix) =((3i±i(√5))/2)  ⇒ix=ln(i)+ln(3±(√5))−ln2  ⇒x=i[ln2−ln(3±(√5))−(π/2)i]           =(π/2)+iln((2/(3±(√5))))=(π/2)−iln(((3±(√5))/2))
sinx=32eixeix=3ie2ix3ieix1=0eix=3i±i52ix=ln(i)+ln(3±5)ln2x=i[ln2ln(3±5)π2i]=π2+iln(23±5)=π2iln(3±52)

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