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Question Number 28702 by students last updated on 29/Jan/18
solve integration  (1/( (√((x−α)(β−x)))))  .
solveintegration1(xα)(βx).
Commented by abdo imad last updated on 29/Jan/18
let use the ch. x= ((α−β)/2)t +((α+β)/2)so  x−α= ((α−β)/2)t +((α+β −2α)/2)=((α−β)/2) (t−1) and   β−x=β−((α+β)/2) −((α−β)/2)t =((β−α)/2) −((α−β)/2)t  = ((α−β)/2)(−1−t) so   I=∫  ? (dx/( (√((x−α)(β−x)))))= ∫      (1/( (√(((α−β)/2)(t−1)((α−β)/2)(−1−1−t)))))((α−β)/2)dt  =(((α−β)/2)/(∣((α−β)/2)∣)) ∫           (dt/( (√(1−t^2 ))))= ξ arcsin(t)+k  = ξ arcsin ( (2/(α−β))(x− ((α+β)/2)))  if α≠β and ξ^2 =1  and we mudt study the case α=β....
letusethech.x=αβ2t+α+β2soxα=αβ2t+α+β2α2=αβ2(t1)andβx=βα+β2αβ2t=βα2αβ2t=αβ2(1t)soI=?dx(xα)(βx)=1αβ2(t1)αβ2(11t)αβ2dt=αβ2αβ2dt1t2=ξarcsin(t)+k=ξarcsin(2αβ(xα+β2))ifαβandξ2=1andwemudtstudythecaseα=β.

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