Menu Close

solve-log-0-5-2-x-log-0-5-x-2-lt-0-




Question Number 172082 by Mikenice last updated on 23/Jun/22
solve  log_(0.5) ^2 x+log_(0.5) x−2<_− 0
solvelog0.52x+log0.5x2<0
Commented by mokys last updated on 23/Jun/22
log_(0.5) ^2 x+log_(0.5) x ≤2  2log_(0.5) x+log_(0.5) x≤2  3log_(0.5) x ≤2   log_(0.5) x≤(2/3)  x≤(0.5)^(2/3)  ≤ ((1/4))^(1/3)      another way :    ((lnx)/(ln(0.5)))≤((2/3)) ⇒lnx ≤((2/3)) ln (0.5)    lnx ≤ ln(0.5)^(2/3)  ⇒ x ≤ (0.5)^(2/3) ≤ ((1/4))^(1/3)     Aldolaimy
log0.52x+log0.5x22log0.5x+log0.5x23log0.5x2log0.5x23x(0.5)23143anotherway:lnxln(0.5)(23)lnx(23)ln(0.5)lnxln(0.5)23x(0.5)23143Aldolaimy

Leave a Reply

Your email address will not be published. Required fields are marked *