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Question Number 172028 by Mikenice last updated on 23/Jun/22
solve: ((log_2 (9−2^(x)) )/(log_2 2^((3−x)) ))=log_2 2
solve:log2(9−2x)log22(3−x)=log22
Answered by Rasheed.Sindhi last updated on 23/Jun/22
((log_2 (9−2^(x)) )/(log_2 2^((3−x)) ))=log_2 2 ((log_2 (9−2^(x)) )/(log_2 2^((3−x)) ))=1 log_2 (9−2^x )=log_2 2^((3−x)) 9−2^x =2^(3−x) 2^x +2^(3−x) =9 9 is sum of powers of 2 9=8+1 9=2^3 +2^0 2^x +2^(3−x) =2^3 +2^0 2^x +2^(3−x) =2^3 +2^(3−3) x=3
log2(9−2x)log22(3−x)=log22log2(9−2x)log22(3−x)=1log2(9−2x)=log22(3−x)9−2x=23−x2x+23−x=99issumofpowersof29=8+19=23+202x+23−x=23+202x+23−x=23+23−3x=3
Commented by Mikenice last updated on 23/Jun/22
yhanks sir
yhankssir

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