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Question Number 172076 by Mikenice last updated on 23/Jun/22
solve log(64(2^(x^2 −40x) )^(1/(24)) )=0
solvelog(642x2−40x24)=0
Answered by puissant last updated on 23/Jun/22
⇒log64+(1/(24))(x^2 −40x)log2=0 ⇒ 6log2=((log2)/(24))(40x−x^2 ) ⇒ x^2 −40x+144=0 Δ=1024 ⇒ (√Δ)=32. x_1 =((40−32)/2) = 4 ; x_2 =((40+32)/2)=36.
⇒log64+124(x2−40x)log2=0⇒6log2=log224(40x−x2)⇒x2−40x+144=0Δ=1024⇒Δ=32.x1=40−322=4;x2=40+322=36.
Answered by mr W last updated on 23/Jun/22
64×(2^(x^2 −40) )^(1/(24)) =1 2^6 ×2^((x^2 −40x)/(24)) =1 2^(((x^2 −40x)/(24))+6) =1 ((x^2 −40x)/(24))+6=0 x^2 −40x+144=0 x=20±16=4 or 36
64×2x2−4024=126×2x2−40x24=12x2−40x24+6=1x2−40x24+6=0x2−40x+144=0x=20±16=4or36

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