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solve-log-x-10-log-x-2-10-6-




Question Number 171847 by Mikenice last updated on 21/Jun/22
solve:  log_x 10+log_x^2  10=6
solve:logx10+logx210=6
Commented by kaivan.ahmadi last updated on 21/Jun/22
log_x 10+(1/2)log_x 10=6⇒(3/2)log_x 10=6⇒  log_x 10=4⇒x^4 =10⇒x=((10))^(1/4)
logx10+12logx10=632logx10=6logx10=4x4=10x=104
Answered by cherokeesay last updated on 21/Jun/22
⇔((ln10)/(lnx))+((ln10)/(2lnx))=6        (x>0)  ((3ln10)/(2lnx))=6⇔10=x^4 ⇔  x_1 =((10))^(1/4) ,  x_2 =((10))^(1/4) i
ln10lnx+ln102lnx=6(x>0)3ln102lnx=610=x4x1=104,x2=104i

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