Solve-p-2-2p-1-q-2p-2q-p-1-2q-2-q-Find-p-q-

Question Number 42528 by rahul 19 last updated on 27/Aug/18

Solve :

\frac{p + 2}{2 p + 1} = \frac{q + 2 p}{2 q + p} = \frac{1 + 2 q}{2 + q} = λ .

Find (p, q) ?

Answered by math1967 last updated on 27/Aug/18

λ = \frac{p + 2 + q + 2 p + 1 + 2 q}{2 p + 1 + 2 q + p + 2 + q} = \frac{3 (p + q + 1)}{3 (p + q + 1)} = 1

∴ \frac{p + 2}{2 p + 1} = 1 \Rightarrow p = 1

\frac{1 + 2 q}{2 + q} = 1 \Rightarrow q = 1

Commented by rahul 19 last updated on 31/Aug/18

thanks sir!