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Solve-plz-4-3-25-4-16-2-




Question Number 186622 by maqsood last updated on 07/Feb/23
   Solve plz      ((√(4+3(√(25+4(√(16)))))))^2
$$\:\:\:\mathrm{Solve}\:\mathrm{plz} \\ $$$$\:\:\:\:\left(\sqrt{\mathrm{4}+\mathrm{3}\sqrt{\mathrm{25}+\mathrm{4}\sqrt{\mathrm{16}}}}\right)^{\mathrm{2}} \\ $$
Commented by maqsood last updated on 07/Feb/23
Process plz
$$\mathrm{Process}\:\mathrm{plz} \\ $$
Commented by mahdipoor last updated on 07/Feb/23
=((√(4+3(√(25+4×4)))))^2 =4+3(√(41))
$$=\left(\sqrt{\mathrm{4}+\mathrm{3}\sqrt{\mathrm{25}+\mathrm{4}×\mathrm{4}}}\right)^{\mathrm{2}} =\mathrm{4}+\mathrm{3}\sqrt{\mathrm{41}} \\ $$
Answered by HeferH last updated on 07/Feb/23
((√(4+3(√(25+4(√(16)))))))^2      = 4+3(√(25+4(√(16))))    = 4 + 3(√(25 + 4∙4))    = 4 + 3(√(25+16))    = 4 + 3(√(41))
$$\left(\sqrt{\mathrm{4}+\mathrm{3}\sqrt{\mathrm{25}+\mathrm{4}\sqrt{\mathrm{16}}}}\right)^{\mathrm{2}} \:\: \\ $$$$\:=\:\mathrm{4}+\mathrm{3}\sqrt{\mathrm{25}+\mathrm{4}\sqrt{\mathrm{16}}}\: \\ $$$$\:=\:\mathrm{4}\:+\:\mathrm{3}\sqrt{\mathrm{25}\:+\:\mathrm{4}\centerdot\mathrm{4}}\: \\ $$$$\:=\:\mathrm{4}\:+\:\mathrm{3}\sqrt{\mathrm{25}+\mathrm{16}}\: \\ $$$$\:=\:\mathrm{4}\:+\:\mathrm{3}\sqrt{\mathrm{41}} \\ $$

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