Solve-sin-2x-2-

Question Number 153593 by tabata last updated on 08/Sep/21

S o l v e : (s i n (2 x))! = 2

Answered by puissant last updated on 08/Sep/21

(s i n (2 x))! = 2! \Rightarrow s i n (2 x) = 2

\Rightarrow \frac{e^{2 i x} - e^{- 2 i x}}{2 i} = 2

\Rightarrow e^{4 i x} - 1 = 4 {i e}^{2 i x}

\Rightarrow e^{i 4 x} - 4 {i e}^{2 i x} - 1 = 0

z = e^{i 2 x}, w e h a v e z^{2} - 4 i z - 1 = 0 . .

\dots \dots \dots . .

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