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Solve-sinx-cosx-sinx-cosx-3-1-3-1-

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Question Number 170752 by balirampatel last updated on 30/May/22
Solve:− ((sinx + cosx)/(sinx − cosx)) = (((√(3 )) − 1)/( (√(3 )) + 1))
Solve:−sinx+cosxsinx−cosx=3−13+1
Answered by Rasheed.Sindhi last updated on 30/May/22
((sinx + cosx)/(sinx − cosx)) = (((√(3 )) − 1)/( (√(3 )) + 1)) determinant ((((a/b)=(c/d)⇒((a+b)/(a−b))=((c+d)/(c−d))))) (((sinx + cosx)+(sinx − cosx))/((sinx + cosx)−(sinx − cosx))) = ((((√(3 )) − 1)+((√(3 )) + 1))/( ((√(3 )) − 1)−((√(3 )) + 1))) ((2sinx)/(2cosx))=((2(√3))/(−2)) tanx=−(√3) x=−(π/3)+nπ
sinx+cosxsinx−cosx=3−13+1ab=cd⇒a+ba−b=c+dc−d(sinx+cosx)+(sinx−cosx)(sinx+cosx)−(sinx−cosx)=(3−1)+(3+1)(3−1)−(3+1)2sinx2cosx=23−2tanx=−3x=−π3+nπ
Answered by Rasheed.Sindhi last updated on 30/May/22
((sinx + cosx)/(sinx − cosx)) = (((√(3 ))+(−1))/( (√(3 )) −(−1))) determinant (((((a+b)/(a−b))=((c+d)/(c−d)) ⇒(a/b)=(c/d)))) ((sinx)/(cosx))=((√3)/(−1)) tanx=−(√3) x=−(π/3)+nπ
sinx+cosxsinx−cosx=3+(−1)3−(−1)a+ba−b=c+dc−d⇒ab=cdsinxcosx=3−1tanx=−3x=−π3+nπ

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