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Solve-t-2-1-dp-dt-p-t-




Question Number 51494 by Tawa1 last updated on 27/Dec/18
Solve:        (t^2  + 1) (dp/dt)  =  p^t
$$\mathrm{Solve}:\:\:\:\:\:\:\:\:\left(\mathrm{t}^{\mathrm{2}} \:+\:\mathrm{1}\right)\:\frac{\mathrm{dp}}{\mathrm{dt}}\:\:=\:\:\mathrm{p}^{\mathrm{t}} \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Dec/18
(t^2 +1)(d^2 p/dt^2 )+(dp/dt)×2t=(d/dt)(p^t )  y=p^t   lny=tlnp  (1/y)(dy/dt)=(t/p)(dp/dt)+lnp  (dy/dt)=y[(t/p)(dp/dt)+lnp]  unique question...force the sleeping cell of brain  to wake up...searching way to solve...
$$\left({t}^{\mathrm{2}} +\mathrm{1}\right)\frac{{d}^{\mathrm{2}} {p}}{{dt}^{\mathrm{2}} }+\frac{{dp}}{{dt}}×\mathrm{2}{t}=\frac{{d}}{{dt}}\left({p}^{{t}} \right) \\ $$$${y}={p}^{{t}} \\ $$$${lny}={tlnp} \\ $$$$\frac{\mathrm{1}}{{y}}\frac{{dy}}{{dt}}=\frac{{t}}{{p}}\frac{{dp}}{{dt}}+{lnp} \\ $$$$\frac{{dy}}{{dt}}={y}\left[\frac{{t}}{{p}}\frac{{dp}}{{dt}}+{lnp}\right] \\ $$$${unique}\:{question}…{force}\:{the}\:{sleeping}\:{cell}\:{of}\:{brain} \\ $$$${to}\:{wake}\:{up}…{searching}\:{way}\:{to}\:{solve}… \\ $$
Commented by Tawa1 last updated on 27/Dec/18
I will wait sir,  thanks for your time. God bless you sir
$$\mathrm{I}\:\mathrm{will}\:\mathrm{wait}\:\mathrm{sir},\:\:\mathrm{thanks}\:\mathrm{for}\:\mathrm{your}\:\mathrm{time}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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