Solve-t-2-1-dp-dt-p-t-

Question Number 51494 by Tawa1 last updated on 27/Dec/18

Solve : (t^{2} + 1) \frac{dp}{dt} = p^{t}

Commented by tanmay.chaudhury50@gmail.com last updated on 27/Dec/18

(t^{2} + 1) \frac{d^{2} p}{{d t}^{2}} + \frac{d p}{d t} \times 2 t = \frac{d}{d t} (p^{t})

y = p^{t}

l n y = t l n p

\frac{1}{y} \frac{d y}{d t} = \frac{t}{p} \frac{d p}{d t} + l n p

\frac{d y}{d t} = y [\frac{t}{p} \frac{d p}{d t} + l n p]

u n i q u e q u e s t i o n \dots f o r c e t h e s l e e p i n g c e l l o f b r a i n

t o w a k e u p \dots s e a r c h i n g w a y t o s o l v e \dots

Commented by Tawa1 last updated on 27/Dec/18

I will wait sir, thanks for your time . God bless you sir

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