Question Number 189345 by Michaelfaraday last updated on 15/Mar/23
$${solve} \\ $$$$\int{t}^{−\mathrm{6}} \left({t}^{\mathrm{2}} +\mathrm{3}\right)^{\mathrm{2}} {dt} \\ $$
Answered by Frix last updated on 15/Mar/23
$$=\int\left(\frac{\mathrm{1}}{{t}^{\mathrm{2}} }+\frac{\mathrm{6}}{{t}^{\mathrm{4}} }+\frac{\mathrm{9}}{{t}^{\mathrm{6}} }\right){dt}=−\frac{\mathrm{1}}{{t}}−\frac{\mathrm{2}}{{t}^{\mathrm{3}} }−\frac{\mathrm{9}}{\mathrm{5}{t}^{\mathrm{5}} }=−\frac{\mathrm{5}{t}^{\mathrm{4}} +\mathrm{10}{t}^{\mathrm{2}} +\mathrm{9}}{\mathrm{5}{t}^{\mathrm{5}} } \\ $$
Commented by Michaelfaraday last updated on 15/Mar/23
$${thanks}\:{sir} \\ $$