solve-tan-x-cot-x-p-sec-x-cos-x-q-

Question Number 115121 by bemath last updated on 23/Sep/20

s o l v e {\begin{cases} \tan x + \cot x = p \\ \sec x - \cos x = q \end{cases}

Commented by ATHISHHUZAIN last updated on 23/Sep/20

f (x) = {\begin{cases} 2 x + 1 o \\ \sec x - \cos x = q \end{cases}

Commented by bemath last updated on 23/Sep/20

? ? ?

Answered by Dwaipayan Shikari last updated on 23/Sep/20

\frac{\sin^{2} x + \cos^{2} x}{sinxcosx} = p \Rightarrow psinx = \frac{1}{cosx}

\frac{1 - \cos^{2} x}{cosx} = q

psinx . \sin^{2} x = q

\sin^{3} x = \frac{q}{p}

sinx = \sqrt[3]{\frac{p}{q}}

x = k π \pm \sin^{- 1} (\sqrt[3]{\frac{p}{q}})